2=45x-4.9x^2

Solution for 2=45x-4.9x^2 equation:

2=45x-4.9x^2

We move all terms to the left:

2-(45x-4.9x^2)=0

We get rid of parentheses

4.9x^2-45x+2=0

a = 4.9; b = -45; c = +2;
Δ = b2-4ac
Δ = -452-4·4.9·2
Δ = 1985.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-\sqrt{1985.8}}{2*4.9}=\frac{45-\sqrt{1985.8}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+\sqrt{1985.8}}{2*4.9}=\frac{45+\sqrt{1985.8}}{9.8}
$